寇仲金
2024-12-25 15:25:37sin4θ = 2sin2θcos2θ sin4θ = 2(2sinθcosθ)(1 - 2sin²θ) sin4θ = 4sinθcosθ - 8sin³θcos²θ
例如,当θ=30°时: sin4(30°) = 4sin(30°)cos(30°) - 8sin³(30°)cos²(30°) sin4(30°) = 4(1/2)(√3/2) - 8(1/4)(3/4) sin4(30°) = 2√3/4 - 3/8 sin4(30°) = (√3 - 3)/8
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其季羡
2024-12-31 13:56:19sin4x = 2sin2x cos2x sin2x = 2sinx cosx sin4x = 2(2sinx cosx) (cos2x) sin4x = 4sinx cosx (cos2x) sin4x = 4sinx cosx (2cos^2x - 1) sin4x = 8sinx cos^3x - 4sinx cosx 这就是坑,别信用sin2x直接计算sin4x。
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